%% %% An UIT Edition example %% %% Example 06-02-12 on page 84. %% %% Copyright (C) 2010 Herbert Voss %% %% It may be distributed and/or modified under the conditions %% of the LaTeX Project Public License, either version 1.3 %% of this license or (at your option) any later version. %% %% See http://www.latex-project.org/lppl.txt for details. %% %% %% ==== % Show page(s) 1 %% \documentclass[]{exaarticle} \pagestyle{empty} \setlength\textwidth{375.57637pt} \AtBeginDocument{\setlength\parindent{0pt}} \usepackage[english]{babel} \usepackage[utf8]{inputenc} \setcounter{section}{6} \StartShownPreambleCommands \usepackage{amsmath} \usepackage[amsmath,thmmarks]{ntheorem} \theoremsymbol{\ensuremath{\triangle}} \theoremprework{\bigskip\hrule} \theorempostwork{\hrule\bigskip} \newtheorem{example}{example}[section] \StopShownPreambleCommands \begin{document} Normal text before the new environment. \begin{example} Use of the transformation theorem: \begin{align*} [z^n]C(z) &= [z^n]\biggl[\frac{e^{3/4}}{\sqrt{1-z}}+e^{-3/4}(1-z)^{1/2}+ \frac{e^{-3/4}}{4}(1-z)^{3/2}+O\Bigl((1-z)^{5/2}\Bigr)\biggr]\\[5pt] &= \frac{e^{-3/4}}{\sqrt{\pi n}}-\frac{5e^{-3/4}}{8\sqrt{\pi n^3}}+ \frac{e^{-3/4}}{128\sqrt{\pi n^5}}+O\biggl(\frac{1}{\sqrt{\pi n^7}}\biggr) \end{align*} \end{example} \end{document}